import os
yourpath = 'd:\\Pyton\\Programs'
exten='*.*'
for root, dirs, files in os.walk(yourpath, topdown=False):
    for name in files:
        print(os.path.join(yourpath, name))
        filedata = name
        with open(name, 'r') as file :
            filedata = file.read()
            filedata = filedata.replace('A','U')
            with open(name, 'w') as file:
                file.write(filedata)
exit()

I have problem this similar to the situation currently being discussed here. I have some CAD files in differerent folders arranged in sequence of years like,
C:\CADfile\1990_dwg
C:\CADfile\1991_dwg
C:\CADfile\1992_dwg
C:\CADfile\1993_dwg
C:\CADfile\1994_dwg
C:\CADfile\19950_dwg
etc. upto the year 2012

The case is this I want my python script to iterate through these folders, create a geodatabase under each name folder and the populate the geodatabase with the feature classes store in the folder
I have been a able to produce a script that can create the geodatabase of the single file and populate it with feature datasets but the problem is I can not ghet the script to go through all the folders and do the same thing.
Please I will be glad to get help on this.
Here is my scripts so far

#Import system modules
import arcpy
import glob
import os
# Set workspace and variables
for year in range(1990,2009): # 1990-2009
    inFolder =  r"c:\data\cadfiles\{0}_dwg".format(year) # 1990_dwg
    gdbName = "d{0}.gdb".format (1990,2009) # d1990.gdb
    arcpy.env.workspace = gdbName
# Create a FileGDB for the fds
arcpy.CreateFileGDB_management("C:/data", "d{0}.gdb".format(year))
reference_scale = "1500"
for file in glob.glob(r"N:\{0}_dwg"):
    outDS = arcpy.ValidateTableName(os.path.splitext("d" + os.path.basename(file))[0])
    arcpy.CADToGeodatabase_conversion(file, gdbName, outDS, reference_scale)

Can anybody help me?
I have some images in one folder and I want to open all the images one by one,
need to do some processing and save it. I try this code, but got an error, as ‘No such file or directory’
on the other hand, when I print the list of images, it work nicely.

path = '/home/Folder/S/'
listing = os.listdir(path)
for infile in listing:
    im = Image.open(infile)
    im.save("out.jpg","JPEG")

This should work:

if filename[0] == '.': # if the first character is a dot
    continue           # skip the file

There are tons of similar programs for windows, and some are even good enough, but I’m not up-to-date on that software – so cannot advise.

You could write the required python script by, e.g., first creating two dicts of {filename: filesize}, and then comparing them to find identical filesizes (and yield the two filenames). This is a suboptimal approach, but that probably doesn’t matter for low numbers of files; for higher numbers, you would want a different approach. (One more suboptimal idea, but slightly better, would be to populate the 1st dict with {size:name}, and then iterate over the files in the 2nd dir, checking for “size in dict”.)

@Paal, you could use a program like ‘fdupes’, which does exactly what you want – de-duplicates the contents of two arbitrary directories.

Anyone who know how to write one of these scripts?

That would be really helpfull!

sorry bout my bad english.

@Priya, you should probably use http://stackoverflow.com/ or http://codereview.stackexchange.com/ to post your code and have volunteers help you with it.

I have to read all these files quickly, so i had generated a list as list.txt=['F:/X/x1.txt','F:/X/x2.txt',F:/X/x3.txt',F:/X/x4.txt',F:/X/x5.txt']

now i have to read list.txt file and i want to generate listres.txt file by ‘w’
where
listres.txt=['F:/X/x1res.txt','F:/X/x2res.txt',F:/X/x3res.txt',F:/X/x4res.txt',F:/X/x5res.txt']

i expect to write result of X1.txt file in X1res.txt alone(X2.txt file in X2res.txt file) but unfortunately it is writing result of all x1+x2+x3+x4+x5 files in x1res files and same result in x2res files how to seperate it?

@Adam: just use the proper filename mask. For example, *.* should not include any files which start with a dot (like .DS_Store). Another way is to check the filename in Python, e.g.

if filename == '.DS_Store':
    continue  # skip the file

Thanks